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NEW QUESTION: 1
You are configuring the high value web content page tag and do not see a .pdf URL on the site map.
You verify that the link to the pdf on the website has the correct Eloqua tracking. What is the solution?
A. Ask the client to add Eloqua tracking scripts to the .pdf
B. Create a subsite to track the .pdf
C. Visit the URL and update the Eloqua Site Map
D. Upload the .pdf to Eloqua Content Assets
Answer: D

NEW QUESTION: 2
A researcher has a sample of 700 observations from a population whose standard deviation is known to be
1,235.6. The mean of the sample is calculated to be 219.2. The null hypothesis is stated as Ho: mean
150 and the alternative is non-directional. The p-value in this case equals ________.
A. 13.88%
B. 6.94%
C. 10.16%
D. 12.82%
Answer: A
Explanation:
Explanation/Reference:
Explanation:
The z-statistic under the null equals (219.2 - 150)/(1235.6/(700

.5)) = 1.48. Since the alternative is non- directional, you must use a two-tailed test and ask the question, "What is the probability of observing a z- statistic at least as large in magnitude as 1.48?" The answer to this will give you the p- value for this sample under the two-tailed test. The right-tailed probability of observing a z-statistic which is at least as big as 1.48 equals 1.0 - 0.9306 = 0.0694 = 6.94%. The left-tailed probability of observing a z-statistic which is at least as small as - 1.48 also equals 6.94% since the standard normal distribution is symmetrical about zero. Therefore, the p-value of this two-tailed test in this sample equals 6.94%*2 = 13.88%.

NEW QUESTION: 3
Which of the following is characterized by an attacker attempting to map out an organization's staff hierarchy in order to send targeted emails?
A. Impersonation
B. Spear phishing
C. Privilege escalation
D. Whaling
Answer: D
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 4
A portion of a VigenEre cipher square is given below using five (1, 2, 14,
16, 22) of the possible 26 alphabets. Using the key word bow, which of
the following is the encryption of the word advance using the
VigenEre cipher?
Exhibit:

A. b r r b b y f
B. b r r b c y f
C. b r r b j y f
D. b r r b b y h
Answer: A
Explanation:
The VigenEre cipher is a polyalphabetic substitution cipher. The key
word bow indicates which alphabets to use. The letter b indicates the
alphabet of row 1, the letter o indicates the alphabet of row 14, and
the letter w indicates the alphabet of row 22. To encrypt, arrange the
key word, repetitively over the plaintext as shown in Table.
Exhibit:

image028
Thus, the letter a of the plaintext is transformed into b of alphabet in row 1, the letter d is transformed into r of row 14, the letter v is transformed into r of row 22 and so on.