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NEW QUESTION: 1
You have a server named Server2 that runs Windows Server 2012 R2. Server2 has the Hyper-V server role installed.
The disks on Server2 are configured as shown in the exhibit. (Click the Exhibit button.)

You create a virtual machine on Server2 named VM1.
You need to ensure that you can configure a pass-through disk for VM1.
What should you do?
A. Take Disk 1 offline.
B. Convert Disk 1 to a MBR disk.
C. Convert Disk 1 to a basic disk.
D. Create a partition on Disk 1.
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Pass-through Disk Configuration
Hyper-V allows virtual machines to access storage mapped directly to the Hyper-V server without requiring the volume be configured. The storage can either be a physical disk internal to the Hyper-V server or it can be a Storage Area Network (SAN) Logical Unit (LUN) mapped to the Hyper-V server. To ensure the Guest has exclusive access to the storage, it must be placed in an Offline state from the Hyper-V server perspective

NEW QUESTION: 2
Refer to the exhibit.

Which six of the following commands are required to configure a dial peer that will allow voice-mail messages to be left on Cisco Unity Express for Unified Communications Manager Express users? The Cisco Unity Express module uses a pilot number of 4100. (Choose six.)
A. codec g711ulaw
B. session target ipv4:10.1.131.2
C. dial-peer voice 4100 voip
D. session target ipv4:10.1.131.1
E. dtmf-relay sip-notify
F. dial-peer voice 4100 pots
G. dtmf-relay h245-alphanumeric
H. codec transparent
I. no vad
J. destination-pattern 4100
Answer: A,B,C,E,I,J

NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
# include <iostream>
# include <map>
# include <vector>
# include <sstream>
# include <string>
using namespace std;
int main() {
int t[] = { 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector<int> v(t, t + 10);
map<int, string> m;
for (vector<int>::iterator i = v.begin(); i != v.end(); i++) {
stringstream s;s << *i << *i;
m.insert(pair<int, string>(*i, s.str()));
}
pair<map<int, string>::iterator, map<int, string>::iterator> range;
range = m.equal_range(6);
for (map<int, string>::iterator i = range.first; i != range.second; i++) { cout << i?>first << " ";
}
return 0;
}
A. program outputs: 6 5
B. program outputs: 6 7
C. program outputs: 6
D. program outputs: 1 5
E. program outputs: 5 7
Answer: C