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NEW QUESTION: 1
Which two technologies are primarily focused on developing Web Services? (Choose two.)
A. UDDI
B. RDBMS
C. WSDL
D. JDBC
E. JSP
Answer: A,C

NEW QUESTION: 2
Which of the following is a hierarchical routing protocol that does not support automatic summarization?
A. RIPv1
B. OSPF
C. RIPv2
D. EIGRP
Answer: B
Explanation:
Explanation/Reference:
Section: Addressing and Routing Protocols in an Existing Network Explanation Explanation:
Open Shortest Path First (OSPF) is a hierarchical, link-state routing protocol that does not support automatic summarization. However, OSPF can be configured to summarize routes at border routers or by using redistribution summarization. OSPF divides an autonomous system (AS) into areas. These areas can be used to limit routing updates to one portion of the network, thereby keeping routing tables small and update traffic low. Only OSPF routers in the same hierarchical area form adjacencies. Hierarchical design provides for efficient performance and scalability. Although OSPF is more difficult to configure, it converges more quickly than most other routing protocols.
Enhanced Interior Gateway Routing Protocol (EIGRP) is a hybrid routing protocol that combines the best features of distance-vector and link-state routing protocols. Unlike OSPF, EIGRP supports automatic summarization and can summarize routes on any EIGRP interface. However, both OSPF and EIGRP converge faster than other routing protocols and support manual configuration of summary routes.
Routing Information Protocol version 1 (RIPv1) and RIPv2 are not hierarchical routing protocols. RIPv1 and RIPv2 are distance-vector routing protocols that use hop count as a metric. By default, RIP sends out routing updates every 30 seconds, and the routing updates are propagated to all RIP routers on the network.
Reference:
CCDA 200-310 Official Cert Guide, Chapter 11, OSPFv2 Summary, p. 439
Cisco: Open Shortest Path First

NEW QUESTION: 3



A. int result = (int)(float)degreesRef;
B. int result = degreesRef;
C. int result = (int)degreesRef;
D. int result = (int)(double)degreesRef;
Answer: A

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