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NEW QUESTION: 1
An enterprise-level customer has recently implemented a pair of bi-directionally IP replicated VNX systems for their highly transactional CIFS file-based environment and NFS Office systems. Each VNX has two storage pools of Flash RAID 5, SAS RAID 5, and NL-SAS RAID 6 for source file systems and SAS. NL- SAS for destination file systems with multiple checkpoints are being taken each day and retained for 30 days.
After a number of months, they have growing concerns that the replication performance has degraded. In addition, the amount of free space available in the source storage pools has been reduced to almost critical levels. They asked your advice on whether to utilize 16 unassigned NL-SAS drives to extend the pools or to purchase additional SAS drives.
How would you advise the customer about the next step?
A. Purchase additional SAS drives to increase the performance and pool sizes
B. Add 8 x NL-SAS drives to the source and destination pools on each system
C. Create a new pool from the NL-SAS drives and relocate all SavVols to it
D. Add 16 x NL-SAS drives to the source pool on each system
Answer: C

NEW QUESTION: 2
a banner ad has the wrong campaign ID tracking parameter (tid instead of cid) on the destination URL.
Which Adobe Analytics feature can be used to fix this issue?
A. Classifications
B. Processing Rules
C. Event Serialization
D. Data Sources
Answer: B

NEW QUESTION: 3
Given the network diagram.

Which address would successfully summarize only the networks seen?
A. 192.168.16.0/21
B. These networks cannot be summarized.
C. 192.168.8.0/21
D. 192.168.8.0/20
E. 192.168.0.0/24
F. 192.168.12.0/20
Answer: C
Explanation:
let's suppose it is a /20 then we would have addresses from 192.168.0.1 to 192.168.15.255
Now let's suppose it is a /21 then we would have addresses from 192.168.8.1 to
192.168.15.255
So both summaries encompass the networks we want to summarize but the second one is the most restrictive one as it only encompasses the networks we were asked to summarize and not others so it is the correct summary.
In fact just count the number of subnets which is 8 and find the exponent of 2 which is 8, that gives you 3 and to find out the summary mask just do /24 - 3 = /21.
if you make it in binary you'll find out the answer too:
the interesting octet is 3rd one so let's convert in binary.
8 0000 1000
9 0000 1001
1 0 0000 1010
1 1 0000 1011
1 2 0000 1100
1 3 0000 1101
1 4 0000 1110
1 5 0000 1111
I've bolded the bits in common there are 5 so 16+5=21 which is mask and address is
1 92.168.8.0