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NEW QUESTION: 1
Where is the largest centre for FX trading?
A. Hong Kong
B. London
C. Singapore
D. New York
Answer: B
NEW QUESTION: 2
ユーザーがDynamoDBを呼び出して特定のデータを取得するモバイルアプリケーションを作成しました。アプリケーションは、DynamoDB SDKとルートアカウントアクセス/シークレットアクセスキーを使用して、モバイルからDynamoDBに接続します。このシナリオのセキュリティのベストプラクティスに関して、以下の記述のどれが当てはまりますか？
A. ユーザーは、DynamoDBおよびEC2アクセスでIAMロールを作成する必要があります。ロールをEC2にアタッチし、モバイルからのすべてのコールをEC2経由でルーティングします
B. DynamoDBアクセスでIAMロールを作成し、モバイルアプリケーションにアタッチします
C. アプリケーションは、Google、Amazon、FacebookなどのIDプロバイダーでDynamoDBへの呼び出しを検証するWeb IDフェデレーションでIAMロールを使用する必要があります
D. ユーザーは、モバイルアプリケーションごとに個別のIAMユーザーを作成し、DynamoDBアクセスを提供する必要があります
Answer: C
Explanation:
Explanation
With AWS IAM a user is creating an application which runs on an EC2 instance and makes requests to AWS, such as DynamoDB or S3 calls. Here it is recommended that the user should not create an IAM user and pass the user's credentials to the application or embed those credentials inside the application. If the user is creating an app that runs on a mobile phone and makes requests to AWS, the user should not create an IAMuser and distribute the user's access key with the app. Instead, he should use an identity provider, such as Login with Amazon, Facebook, or Google to authenticate the users, and then use that identity to get temporary security credentials.
NEW QUESTION: 3
이진 형식으로 표시된 다음 IPv4 주소를 점으로 구분된 십진수 형식으로 변환
10101100.01111011.00001101.10011101
A. 172.124.13.57
B. 173.13.13.157
C. 172.122.13.15
D. 172.123.13.157
Answer: D
Explanation:
An IPv4 address in dotted decimal format is constructed using binary arithmetic. In binary arithmetic, each bit within a group represents a power of two. Specifically, the first bit in a group represents 2 to the power of 0, the second bit represents 2 to the power of 1, the third bit represents 2 to the power of 2, and so on. Binary format is simple because each successive bit in a group is exactly twice the value of the previous bit.
The first octet is 128+32+8+4=172
The second octet 64+32+16+8+2+1=123
The third octet 8+4+1= 13
The fourth octet is 128+16+8+4+1= 157
Reference: https://en.wikipedia.org/wiki/IPv4
NEW QUESTION: 4
Which one of these statements best describes how the ProxySG locates an object in its cache?
A. The ProxySG uses the hostname in the object's URL to determine in which cache directory the object is located.
B. The ProxySG performs a hash against the URL of the object and uses the hash as the basis for a lookup into the table of cached objects.
C. The ProxySG uses the first 32 bytes of the object's URL to determine in which cache directory the object is located.
Answer: B