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NEW QUESTION: 1
Which two statements describe the operation of the CSMA/CD access method? (Choose two.)
A. In a CSMA/CD collision domain, stations must wait until the media is not in use before transmitting.
B. After a collision, all stations involved run an identical backoff algorithm and then synchronize with each other prior to transmitting data.
C. After a collision, the station that detected the collision has first priority to resend the lost data.
D. In a CSMA/CD collision domain, multiple stations can successfully transmit data simultaneously.
E. After a collision, all stations run a random backoff algorithm. When the backoff delay period has expired, all stations have equal priority to transmit data.
F. The use of hubs to enlarge the size of collision domains is one way to improve the operation of the CSMA/CD access method.
Answer: A,E
Explanation:
Ethernet networking uses Carrier Sense Multiple Access with Collision Detect (CSMA/CD), a protocol that helps devices share the bandwidth evenly without having two devices transmit at the same time on the network medium.
CSMA/CD was created to overcome the problem of those collisions that occur when packets are transmitted simultaneously from different nodes. And trust me, good collision management is crucial, because when a node transmits in a CSMA/CD network, all the other nodes on the network receive and examine that transmission. Only bridges and routers can effectively prevent a transmission from propagating throughout the entire network! So, how does the CSMA/CD protocol work? Like this: when a host wants to transmit over the network, it first checks for the presence of a digital signal on the wire. If all is clear (no other host is transmitting), the host will then proceed with its transmission. But it doesn't stop there. The transmitting host constantly monitors the wire to make sure no other hosts begin transmitting. If the host detects another signal on the wire, it sends out an extended jam signal that causes all nodes on the segment to stop sending data (think, busy signal). The nodes respond to that jam signal by waiting a while before attempting to transmit again. Backoff algorithms determine when the colliding stations can retransmit. If collisions keep occurring after 15 tries, the nodes attempting to transmit will then time out.

NEW QUESTION: 2
Sharleef Nettleton, a quantitative analyst with Churn Brothers Brokerage, is examining a data sample and has amassed the following information:
Standard deviation of the sample: 2.90
Number of observations: 68
Degrees of freedom: 2
Sample mean: 114
Assume that Ms. Nettleton formulates a null hypothesis that states that the value of the population mean is zero. Additionally, assume that the population standard deviation is unknown. Given this information, what is the standard error of the estimate? Further, what is the test statistic? Choose the best answer.
A. None of these answers is correct.
B. 0.3517; 84.34
C. 0.3570; 319.38
D. 1.0199; 56.44
E. 0.3517; 324.14
F. 1.0199; 111.78
G. 0.3570; 29.91
Answer: E
Explanation:
Explanation/Reference:
Explanation:
If the population standard deviation is unknown, as in this example, the standard error of the estimate is found by using the following equation:
{Standard error = s / square root of n} where s = the sample standard deviation and n = the number of observations in the sample.
In this example, all of the necessary information has been provided, and the determination of the standard error of the estimate is found as:
{Standard error = [2.90 / 8.2462] = 0.3517}
Now that the standard error of the estimate has been calculated, the test statistic can be found by using the following equation:
{Test statistic = [sample statistic - value of the population parameter under the null hypothesis] / standard error of the sample statistic].
Again, all of the necessary information has been provided, and the calculation of the test statistic is found as follows:
{Test statistic = [114 - 0] / 0.3517 = 324.14}
This is a very large test statistic and the null hypothesis will likely be rejected unless a very low level of confidence is employed.

NEW QUESTION: 3
What features are available to users when integrating Lotus Quickr and Lotus Connections?
A. Lotus Connections Profile business card displays for Lotus Quickr users.
B. From a Lotus Connections activity a user can publish content to a LotusQuickr Library.
C. All of the above.
D. From a Lotus Connections community a user can create a Lotus QuickrPlace, Wiki, or Blog.
Answer: C
Explanation:
Reference:http://publib.boulder.ibm.com/infocenter/lqkrhelp/v8r0/index.jsp?topic=/com.ibm.lotus.q uickr.admin.wpv81.doc/connections/lotusconnectionsfeaturesinlotusquickr.html

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