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NEW QUESTION: 1
Node A is a member of SAN Zone 1 and SAN Zone 2. Node B is a member of SAN Zone 2. Node B has just been replaced and the storage administrator is troubleshooting connectivity issues between Node A and Node B.
Which of the following is the MOST likely cause of the issue?
A. Zone configuration is causing undesired Registered State Change Notification events.
B. Nodes cannot be a member of multiple zones.
C. Zone configuration may need to be updated with the new port WWN.
D. Node B is an unauthorized host cabled to the wrong SAN switch.
Answer: C

NEW QUESTION: 2
If Organization A trusts Organization B and Organization B trusts Organization C, then Organization A trusts Organization C. Which of the following PKI concepts is this describing?
A. Public key trust
B. Certificate authority trust
C. Transitive trust
D. Domain level trust
Answer: C
Explanation:
Explanation/Reference:
Explanation:
In transitive trusts, trust between a first party and a third party flows through a second party that is trusted by both the first party and the third party.

NEW QUESTION: 3
100万行を含むTable1という名前のテーブルがあります。 Table1には、機密情報を格納するColumn1という名前の列が含まれています。 Column1はnvarchar(16)データ型を使用します。
Cert1という名前の証明書があります。
Column1を、一方向ハッシュを使用するColumn2という名前の新しい暗号化列に置き換える必要があります。
Column1を削除する前に、どのコードセグメントを実行する必要がありますか?
回答するには、適切なコードセグメントをコードセグメントのリストから回答領域に移動し、正しい順序に並べます。

Answer:
Explanation:

Explanation:
Note:
* There are a few different hashing algorithms available in SQL Server 2005: MD2, MD4, MD5, SHA, SHA1, with each having pros and cons.
* In cryptography, SHA-1 is a cryptographic hash function designed by the United States National Security Agencyand published by the United StatesNISTas a USFederal Information Processing Standard.SHA stands for "secure hash algorithm".The four SHAalgorithmsare structured differently and are distinguished asSHA-0,SHA-1,SHA-2, andSHA-3.SHA-1 is very similar to SHA-0, but corrects an error in the original SHA hash specification that led to significant weaknesses.The SHA-0 algorithm was not adopted by many applications.SHA-2 on the other hand significantly differs from the SHA-1 hash function.
SHA-1 is the most widely used of the existing SHA hash functions, and is employed in several widely used applications and protocols.
* To encrypt a column of data using a simple symmetric encryption
In Object Explorer, connect to an instance of Database Engine.
On the Standard bar, click New Query.
Copy and paste the following example into the query window and click Execute.
USE AdventureWorks2012;
--If there is no master key, create one now.
IF NOT EXISTS
(SELECT * FROM sys.symmetric_keys WHERE symmetric_key_id = 101)
CREATE MASTER KEY ENCRYPTION BY
PASSWORD = '23987hxJKL95QYV4369#ghf0%lekjg5k3fd117r$$#1946kcj$n44ncjhdlj' GO CREATE CERTIFICATE Sales09 WITH SUBJECT = 'Customer Credit Card Numbers'; GO CREATE SYMMETRIC KEY CreditCards_Key11 WITH ALGORITHM = AES_256 ENCRYPTION BY CERTIFICATE Sales09; GO
-- Create a column in which to store the encrypted data.
ALTER TABLE Sales.CreditCard
ADD CardNumber_Encryptedvarbinary(128);
GO
-- Open the symmetric key with which to encrypt the data.
OPEN SYMMETRIC KEY CreditCards_Key11
DECRYPTION BY CERTIFICATE Sales09;
-- Encrypt the value in column CardNumber using the
-- symmetric key CreditCards_Key11.
-- Save the result in column CardNumber_Encrypted.
UPDATE Sales.CreditCard
SET CardNumber_Encrypted = EncryptByKey(Key_GUID('CreditCards_Key11')
, CardNumber, 1, HashBytes('SHA1', CONVERT( varbinary
, CreditCardID)));
GO
Reference:
Ref: http://www.mssqltips.com/sqlservertip/2431/sql-server-column-level-encryption-example-using-symmetric-keys/

NEW QUESTION: 4
When configuring a new Ethernet Routing Switch (ERS) 8000 using the default interface, the attempt to load an ACLI configuration fails because the default interface is the CLI. How is the ACLI interface obtained?
A. Change the interface type in the config.cfg file.
B. Change the ACLI boot flag and save the boot configuration file.
C. Use the abort command and enter 'no' at the default interface.
D. Exit the CLI and choose ACLI at the interface manager prompt.
Answer: D

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