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NEW QUESTION: 1
Select three benefits of using the OUM Manage Focus Area on an implementation.
A. The client creates and produces project plans that drive the project.
B. It supports improved communication.
C. It encourages early client involvement.
D. It manages acceptance of work products.
E. It focuses on accurate estimating.
F. It allows for quicker project durations.
Answer: B,C,D
Explanation:
Explanation: /The Manage focus area provides a framework in which all types of projects can be planned, estimated,controlled, and completed in a consistent manner. Oracle's Project Management Method (PJM) is partof the Manage focus area. Consistency is required in today's business environment, where projectsoften implement packages, develop application extensions, and create a data warehouse in order tosatisfy a business need.
Project management enables the project manager to manage delivery of an agreed upon level of solution quality while planning for and controlling the scope, cost, and schedule.
The Manage focus area has three phases:
*Project Start Up Phase
*Project Execution and Control Phase
*Project Closure Phase
/Collectively, the processes listed below form a comprehensive set of tasks required to manage Oracle-based development and implementation projects. Every project includes most, if not all, of these processes, whether they are the responsibility of a consulting organization, a client organization, or a third party.
The Manage focus area is organized into 13 processes:
Bid Transition
Scope Management
Financial Management
(A)Work Management
Risk Management
Issue and Problem Management
Staff Management
(C)Communication Management
Quality Management
Configuration Management
Infrastructure Management
Procurement Management
Organizational Change Management
/OUM Manage Focus Area
NEW QUESTION: 2
Scenario:
CGE decided to virtualize its infrastructure workloads and provide a virtual solution to all end users. The infrastructure workloads include Delivery Controllers, StoreFront servers, License Servers, and Microsoft SQL Servers for databases.
How should the resource pools be designed to host the infrastructure workloads and virtual desktops to ensure high availability?
A. Separate the workloads by roles and group them as a XenServer resource pool. Each XenServer resource pool should comprise a maximum of 16 XenServer hosts. Multiple storage repositories need to be implemented for central storage of virtual disks, as well as for XenMotion and high availability between resource pools and backup for disaster recovery purposes.
B. Separate the workloads by roles and group them as a XenServer resource pool to reflect the OU structure of Active Directory. Each XenServer resource pool should comprise a maximum of
24 XenServer hosts. A storage repository needs to be implemented for central storage of virtual disks, as well as for XenMotion, high availability, and backup for disaster recovery purposes.
C. Separate the workloads by roles and group them as a XenServer resource pool to ensure that the workloads can be streamed by Provisioning Services, including XenServer. Each XenServer resource pool should comprise a maximum of 32 XenServer hosts. Multiple storage repositories need to be implemented for central storage of virtual disks, as well as for XenMotion, high availability between resource pools, and backup for disaster recovery purposes.
D. Separate the workloads by roles and group them as a XenServer resource pool to ensure easier management, fewer workload conflicts, and support for disaster recovery. Each XenServer resource pool should comprise a maximum of eight XenServer hosts. A storage repository needs to be implemented for central storage of virtual disks, as well as for XenMotion, high availability, and backup for disaster recovery purposes.
Answer: D
NEW QUESTION: 3
偽装された送信元アドレスを持つパケットを転送する代わりにドロップできる技術はどれですか？
A. ICUPリダイレクト
B. SNMPv3
C. ICMP到達不能メッセージ
D. TACACS +
E. uRPF
Answer: C
NEW QUESTION: 4
Given:
3 0. public boolean X(byte[] Y) throws IllegalArgumentException {
3 1. ByteArrayInputStream bais = new ByteArrayInputStream(arg);
3 2. DataInputStream dis = new DataInputStream(bais);
3 3. String type = null;
3 4. try {type = dis.readUTF();}
3 5. catch (Exception e) { }
3 6. return(Z);
3 7. }
Which substitutions for X, Y, and Z in the code create a valid implementation of RecordFilter that matches records whose type is NOT deleted?
A. X is matches
Y is type
Z is !type.equals("deleted")
B. X is match
Y is arg
Z is type.equals("deleted")
C. X is matches
Y is arg
Z is type.equals("deleted")
D. X is matches
Y is arg
Z is !type.equals("deleted")
E. X is match
Y is type
Z is !type.equals("deleted")
Answer: D