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NEW QUESTION: 1
Welche zwei Befehlssequenzen müssen Sie beim Switch konfigurieren, um einen Layer 3 EtherChannel mit einem Open-Standard-Protokoll einzurichten? (Wähle zwei )
A. interface port-channel 10
switchport
switchport mode trunk
B. interface GigabitEthernet0/0/1
channel-group 10 mode on
C. interface GigabitEthernet0/0/1
channel-group 10 mode auto
D. interface GigabitEthernet0/0/1
channel-group 10 mode active
E. interface port-channel 10
no switchport
ip address 172.16.0.1.255.255.255.0
Answer: D,E

NEW QUESTION: 2
Which three MDX policies would require a re-installation of the applications in order to be refreshed on the device when attempting to troubleshoot a policy-related issue? (Choose three.)
A. Enable encryption
B. Network access
C. Security Group
D. WorxMail Exchange Server FQDN
E. Export Contacts
F. Allowed URLs
Answer: A,C,D

NEW QUESTION: 3
If an Ethernet port on a router was assigned an IP address of 172.16.112.1/20, what is the maximum number of hosts allowed on this subnet?
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: C
Explanation:
Each octet represents eight bits. The bits, in turn, represent (from left to right): 128, 64, 32 , 16 , 8, 4, 2, 1 Add them up and you get 255. Add one for the all zeros option, and the total is 256. Now, take away one of these for the network address (all zeros) and another for the broadcast address (all ones). Each octet represents 254 possible hosts. Or 254 possible networks. Unless you have subnet zero set on your network gear, in which case you could conceivably have 255. The CIDR addressing format (/20) tells us that 20 bits are used for the network portion, so the maximum number of networks are 2

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20 minus one if you have subnet zero enabled, or minus 2 if not. You asked about the number of hosts. That will be 32 minus the number of network bits, minus two. So calculate it as (2
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