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NEW QUESTION: 1
One of your Linux systems was compromised last night. According to change management history and a recent vulnerability scan, the system's patches were up-to-date at the time of the attack. Which of the following statements is the Most Likely explanation?
A. It was a man-in-middle exploit.
B. It was a zero-day exploit.
C. It was a Trojan Horse exploit.
D. It was a worm exploit.
Answer: B

NEW QUESTION: 2
Which of the following address and subnet mask combinations summarizes the smallest network?
A. 172.31.148.0/24
B. 172.16.2.0/16
C. 172.16.1.0/8
D. 172.20.3.0/21
Answer: A
Explanation:
Explanation/Reference:
Section: Addressing and Routing Protocols in an Existing Network Explanation Explanation:
Of the available choices, the 172.31.148.0/24 network address and subnet mask combination summarizes the smallest network. The /24 notation indicates that a 24-bit subnet mask (255.255.255.0) is used. A 24- bit subnet is typically used to represent a single Class C, 256-host subnet. In this scenario, the
172.31.148.0/24 network is a 256-host subnet of the Class B 172.31.0.0 network. The 256-host subnet's network address is 172.31.148.0. Its broadcast address is 172.31.148.255. In its classful form, this network would be represented by a /16 subnet mask (255.255.0.0) and contain a total of 65,534 hosts. The Class B range network address would be 172.31.0.0. The broadcast address would be 172.31.255.255.
The 172.20.3.0/21 network address and subnet mask combination does not summarize the smallest network. The /21 notation indicates that a 21bit subnet mask (255.255.248.0) is used, which can summarize two /22 networks, four /23 networks, eight /24 networks, and so on. In this scenario, the
172.20.3.0/21 subnet results in a subnet that can support 2,046 hosts. This subnet's network address is
172.20.0.0. Its broadcast address is 172.20.7.255. The next subnet of addresses from the Class B range would thus have a network address of 172.20.8.0. If this subnet were also a /21, it would have a broadcast address of 172.20.15.255.
The 172.16.2.0/16 network address and subnet mask combination does not summarize the smallest network. The /16 notation indicates that a 16bit subnet mask (255.255.0.0) is used. This subnet mask in fact encompasses the entire classful 172.16.0.0 network range. Therefore, the network address of the
172.16.2.0/16 network is 172.16.0.0. Its broadcast address is 172.16.255.255, for a total of 65,534 hosts.
The 172.16.1.0/8 network address and subnet mask combination does not summarize the smallest network. The /8 notation indicates that an eightbit subnet mask (255.0.0.0) is used. This subnet mask encompasses a range of 16,777,214 IP addresses. For example, the Class A 10.0.0.0 network is a /8 range of IP addresses. In this scenario, the 172.16.1.0/8 network would include every address in the range from 172.0.0.0 through 172.255.255.255.
Reference:
CCDA 200-310 Official Cert Guide, Chapter 8, IPv4 Address Subnets, pp. 302-310 Cisco: IP Routing Frequently Asked Questions: Q.
What does route summarization mean?
Cisco: IP Addressing and Subnetting for New Users

NEW QUESTION: 3
HOTSPOT
You are developing an SQL Server database for an automobile manufacturer. The manufacturer maintains the list of vehicles sold and vehicles that have been recalled. The tables are shown below:

You have the following Transact-SQL code. Line numbers are included for reference only.

You must update the VehiclesToRecall table with the list of vehicles that were recalled in 2014. You must maximize the performance of the operation.
For each of the following statements, select Yes if the statement is true. Otherwise, select No.
Hot Area:

Answer:
Explanation:

Explanation/Reference:
Reference: MERGE (Transact-SQL)
https://msdn.microsoft.com/en-us/library/bb510625.aspx