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NEW QUESTION: 1
You have an Office 365 subscription.
A new compliance policy requires that a Microsoft Exchange Server administrator must be able to search all user email messages.
You add the Exchange administrator to the Discovery Management role group.
You need to deploy an eDiscovery Center in Microsoft SharePoint Online.
Which three actions should you perform? Each correct answer presents part of the solution.
NOTE: Each correct selection is worth one point.
A. From search in the SharePoint admin center, add Exchange Online as a Result
Resources.
B. From the Site settings of the eDiscovery Center, add Exchange Online as Result
Resources.
C. From the SharePoint admin center, create an eDiscovery Center as a site collection.
D. From the Site settings of the eDiscovery Center, add the Exchange administrator as an owner of the eDiscovery Center.
E. From search in the SharePoint admin center, import a search configuration.
Answer: B,C,D
NEW QUESTION: 2
単一のネットワークデバイスでクライアントモードの信頼されたサーバーにNTPを構成するには、どの2つのタスクを実行する必要がありますか？ （2つ選択してください）
A. タイムゾーンを確認します。
B. NTP認証を有効にします。
C. NTPサーバーのIPアドレスを指定します
D. NTPサーバーの秘密鍵を設定する
E. NTPブロードキャストを無効にする
Answer: C,D
NEW QUESTION: 3
When teaching a client about anti-retroviral therapy for human immunodeficiency virus (HIV), the PN should emphasize:
A. when started, therapy must not be interrupted to prevent opportunistic infection.
B. therapy should be interrupted for one week every three months to prevent toxicity.
C. when started, therapy must not be interrupted to prevent viral resistance.
D. therapy should be interrupted for one day each month to prevent toxicity.
Answer: C
Explanation:
HIV mutates very rapidly, and any interruption of therapy can allow viral resistance to emerge-even taking a dose late. Choice 2 is incorrect because, when the virus is kept in check with antiretrovirals, the client's own immune system is able to keep opportunistic infections at bay. Choices 3 and 4 are incorrect because therapy should not be interrupted for any reason. If the client develops toxicity, another antiretroviral drug might be prescribed.Physiological Adaptation
NEW QUESTION: 4
Given:
class Erupt implements Runnable {
public void run() {
System.out.print(Thread.currentThread().getName());
}
}
public class Yellowstone {
static Erupt e = Erupt();
Yellowstone() { new Thread(e, "const").start(); } // line A
public static void main(String[] args) {
new Yellowstone();
new Faithful().go();
}
static class Faithful {
void go() { new Thread(e, "inner").start(); } // line B
}
}
What is the result?
A. Both const and inner will be in the output.
B. Compilation fails due to an error on line B.
C. Only const will be in the output.
D. An exception is thrown at runtime.
E. Compilation fails due to an error on line A.
Answer: A
Explanation:
The code compiles fine.
Note: The Runnable interface should be implemented by any class whose instances are intended to be executed by a thread. The class must define a method of no arguments
called run.
This interface is designed to provide a common protocol for objects that wish to execute
code while they are active. For example, Runnable is implemented by class Thread. Being
active simply means that a thread has been started and has not yet been stopped.
In addition, Runnable provides the means for a class to be active while not subclassing
Thread. A class that implements Runnable can run without subclassing Thread by
instantiating a Thread instance and passing itself in as the target. In most cases, the
Runnable interface should be used if you are only planning to override the run() method
and no other Thread methods. This is important because classes should not be subclassed
unless the programmer intends on modifying or enhancing the fundamental behavior of the
class.
Note 2: start()
Causes this thread to begin execution; the Java Virtual Machine calls the run method of
this thread.
Reference: java.lang
Interface Runnable