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NEW QUESTION: 1
After creating an instance, which two methods can be used to find the status of the instance?
A. View the instance on the Instances page of the web console.
B. Use the API call GET /instancestatus/.
C. View the instance orchestration on the Orchestrations page of the web console.
D. Use the API call GET /instance/ with the Accept header application/oracle-compute-v3+directory+json.
Answer: A,D
Explanation:
Explanation
Reference
https://docs.oracle.com/cloud/latest/stcomputecs/STCSG/GUID-12C08FE7-B5E7-460E-AD83-37D163CB48FB
https://docs.oracle.com/cloud/latest/stcomputecs/STCSA/op-instance-%7Bname%7D-get.html

NEW QUESTION: 2
ある会社が、VPCのプライベートサブネットでホストされているAmazonEC2インスタンスでアプリケーションを実行しています。 EC2インスタンスは、Elastic Load Balancer（ELB）の背後にあるAuto Scalingグループで構成されます。EC2インスタンスはアウトバウンドインターネットアクセスにNATゲートウェイを使用しますが、EC2インスタンスはパブリックインターネットに接続してソフトウェアアップデートをダウンロードできません。この問題の根本的な原因は？ （2つ選択してください）
A. EC2インスタンスにアタッチされたセキュリティグループのアウトバウンドルールが正しく設定されていません。
B. NATゲートウェイに接続されているセキュリティグループが正しく構成されていません
C. VPCのルートテーブルが正しく設定されていません
D. ELBが適切なヘルスチェックで構成されていません
E. EC2インスタンスはElasticIPアドレスに関連付けられていません
Answer: A,C

NEW QUESTION: 3
You have a Microsoft 365 Enterprise subscription.
You create a password policy as shown in the following exhibit.

Use the drop-down menus to select the answer choice that completes each statement based on the information presented in the graphic.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

By default, smart lockout locks the account from sign-in attempts for one minute after 10 failed attempts. In this question, the lockout threshold if 5 failed attempts. The account locks again after each subsequent failed sign-in attempt, for one minute at first and longer in subsequent attempts.
Password evaluation goes through several steps including normalization and Substring matching which is used on the normalized password to check for the user's first and last name as well as the tenant name.
The next step is to identify all instances of banned passwords in the user's normalized new password. Then:
* Each banned password that is found in a user's password is given one point.
* Each remaining unique character is given one point.
* A password must be at least five (5) points for it to be accepted.
Conto$01Pa$$word contains two banned passwords and no remaining unique characters so is given a score of
2 points. This is less than the required 5 points so will be rejected.
Pa$$w0rd contains a banned password and no remaining unique characters so is given a score of 1 point. This is less than the required 5 points so will be rejected.
AzureAD!!111 contains a banned password (AzureAD!!) and has three remaining characters. However, the remaining characters are all the same (they're all 1s) so that is only one unique character. So that password will be given a score of 2. One for the banned password and 1 for the unique character. This is less than the required 5 points so will be rejected.
Password11 does not contain a banned password. Password11 contains 10 characters. However, there are two
's' and two '1' so there are 8 unique characters. Therefore, the password will be given a score of 8 points. This is more than the required 5 points so the password will be accepted.
Reference:
https://docs.microsoft.com/en-us/azure/active-directory/authentication/concept-password-ban-bad
https://docs.microsoft.com/en-us/azure/active-directory/authentication/howto-password-smart-lockout

NEW QUESTION: 4
What firewall kernel table stores information about port allocations for Hide NAT connections?
A. NAT_alloc
B. NAT_dst_any_list
C. fwx_alloc
D. NAT_src_any_list
Answer: C