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NEW QUESTION: 1

A. Option F
B. Option E
C. Option C
D. Option A
E. Option G
F. Option D
G. Option B
Answer: E,G
Explanation:
Since static routing is a manual process, it can be argued that it is more secure (and more prone to human errors) since the network administrator will need to make changes to the routing table directly. Also, in stub networks where there is only a single uplink connection, the load is reduced as stub routers just need a single static default route, instead of many routes that all have the same next hop IP address.

NEW QUESTION: 2
組み込みの認証および承認機能を使用するAzure APIアプリを実装しています。
すべてのアプリアクションは、現在のユーザーに関する情報に関連付ける必要があります。
現在のユーザーに関する情報を取得する必要があります。
目標を達成するための2つの可能な方法は何ですか？それぞれの正解は完全な解決策を示します。
注：それぞれの正しい選択には1ポイントの価値があります。
A. 環境変数
B. /.auth/me HTTPエンドポイント
C. HTTPヘッダー
D. /.auth/loginエンドポイント
Answer: B,C
Explanation:
A: After App Service Authentication has been configured, users trying to access your API are prompted to sign in with their organizational account that belongs to the same Azure AD as the Azure AD application used to secure the API. After signing in, you are able to access the information about the current user through the HttpContext.Current.User property.
C: While the server code has access to request headers, client code can access GET /.auth/me to get the same access tokens ( References:
https://docs.microsoft.com/en-us/azure/app-service/app-service-web-tutorial-auth-aad
https://docs.microsoft.com/en-us/sharepoint/dev/spfx/web-parts/guidance/connect-to-api-secured-with-aad

NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An
answer choice may be correct for more than one question in the series. Each question is
independent of the other questions in this series.
Information and details provided in a question apply only to that question.
You have a Microsoft SQL Server database named DB1 that contains the following tables:

There are no foreign key relationships between TBL1 and TBL2.
You need to create a query that includes data from both tables and minimizes the amount of time required
for the query to return data.
What should you do?
A. Drop existing indexes on TBL1 and then create a clustered columnstore index.
Create a nonclustered columnstore index on TBL1.Create a nonclustered index on TBL2.
B. Create a clustered index on TBL1.
Create a nonclustered index on TBL2 and add the most frequently queried column as included
columns.
C. Drop existing indexes on TBL1 and then create a clustered columnstore index.
Create a nonclustered columnstore index on TBL1.Make no changes to TBL2.
D. Create clustered indexes on TBL1 and TBL2.
E. Create UNIQUE constraints on both TBL1 and TBL2.
Create a partitioned view that combines columns from TBL1 and TBL2.
F. Create an indexed view that combines columns from TBL1 and TBL2.
G. Create CHECK constraints on both TBL1 and TBL2.
Create a partitioned view that combines columns from TBL1 and TBL2.
H. Create a nonclustered index on TBL2 only.
Answer: G
Explanation:
Explanation/Reference:
Explanation:
A partitioned view is a view defined by a UNION ALL of member tables structured in the same way, but
stored separately as multiple tables in either the same instance of SQL Server or in a group of autonomous
instances of SQL Server servers, called federated database servers.
Conditions for Creating Partitioned Views Include:
The select list
All columns in the member tables should be selected in the column list of the view definition.

The columns in the same ordinal position of each select list should be of the same type, including

collations. It is not sufficient for the columns to be implicitly convertible types, as is generally the case
for UNION.
Also, at least one column (for example <col>) must appear in all the select lists in the same ordinal
position. This <col> should be defined in a way that the member tables T1, ..., Tn have CHECK constraints
C1, ..., Cn defined on <col>, respectively.
References:
https://docs.microsoft.com/en-us/sql/t-sql/statements/create-view-transact-sql

NEW QUESTION: 4
Which options are available when configuring a link aggregation bond in the Cisco UCS Invicta management interface?
A. DNS, GSLB, SLB
B. TCP, UDP
C. Round robin, active backup, LACP, ALB
D. LACP, ISL
Answer: C
Explanation:
Reference:http://www.cisco.com/c/en/us/td/docs/unified_computing/ucs/invicta/scaling_system/50 12/admin/scalingsystem-admcfg-5012/scalingsystemadmcfg-5012-cfg.html(table 3-1)