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NEW QUESTION: 1
Which of the following statement about snooping is true?
A. It is the art of convincing people and making them disclose useful information such as account names and passwords.
B. It is a technique that makes a transmission appear to have come from an authentic source by forging the IP address.
C. It occurs when an unauthorized user tries to log on repeatedly to a computer or network by guessing usernames and passwords.
D. It is an activity of observing the content that appears on a computer monitor or watching what a user is typing.
Answer: D
NEW QUESTION: 2
In order to meet the business goals of the company, which software should the company install on its server?
A. Microsoft Windows Small Business Server Standard
B. Microsoft Windows Essential Business Server Standard
C. Microsoft Windows Small Business Server Premium
D. Microsoft Windows Essential Business Server Premium
Answer: C
NEW QUESTION: 3
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the top half of the students arranged by their average marks must be given a rank of 1 and the remaining students must be given a rank of 2.
Which Transact-SQL query should you use?
A. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS RankFROM StudentMarks) tmpWHERE Rank = 1
B. SELECT StudentCode as Code,DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS ValueFROM StudentMarksGROUP BY StudentCode
C. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS RankFROM StudentMarks) tmpWHERE Rank = 1
D. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS RankFROM StudentMarks) tmpWHERE Rank = 1
E. SELECT StudentCode as Code,NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS ValueFROM StudentMarksGROUP BY StudentCode
F. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS RankFROM StudentMarks) tmpWHERE Rank = 1
G. SELECT StudentCode as Code,RANK() OVER (ORDER BY AVG (Marks) DESC) AS ValueFROM StudentMarksGROUP BY StudentCode
H. SELECT Id, Name, Marks,DENSE_RANK() OVER (ORDER BY Marks DESC) AS RankFROM StudentMarks
Answer: E