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NEW QUESTION: 1
You are designing a table for a SQL Server database. The table uses horizontal partitioning.
You have the following requirements:
Each record in the table requires a unique key.

You must minimize table fragmentation as the table grows.

You need to choose the appropriate data type for the key value.
What should you do?
A. Generate a random value that uses the char(16) data type.
B. Use the NEWID function to create a unique identifier.
C. Use the NEWSEQUENTIALID function to create a unique identifier.
D. Generate a random value that uses the bigint datatype.
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Horizontal partitioning divides a table into multiple tables. Each table then contains the same number of columns, but fewer rows. For example, a table that contains 1 billion rows could be partitioned horizontally into 12 tables, with each smaller table representing one month of data for a specific year. Any queries requiring data for a specific month only reference the appropriate table.
NEWSEQUENTIALID creates a GUID that is greater than any GUID previously generated by this function on a specified computer since Windows was started. After restarting Windows, the GUID can start again from a lower range, but is still globally unique. When a GUID column is used as a row identifier, using NEWSEQUENTIALID can be faster than using the NEWID function. This is because the NEWID function causes random activity and uses fewer cached data pages. Using NEWSEQUENTIALID also helps to completely fill the data and index pages.
References:https://msdn.microsoft.com/en-us/library/ms189786.aspx

NEW QUESTION: 2
You have created a Web Intelligence document that displays data from the query in a single table. Now you edit the query and add two additional objects.
Where will the new objects appear when you re-run the query?
A. In the Document Summary panel
B. In the existing table
C. In a new table
D. In the Available Objects panel
Answer: D

NEW QUESTION: 3
What is the purpose of the highlighted parameter in the following SQL statement?

A. saving temporary storage allocation space
B. Nothing; it is only a comment.
C. optimizer hint to not use the specified spatial index
D. optimizer hint to use the specified spatial index
E. optimizer hint to create a spatial index on the table
Answer: D

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