Place the components on the left in the correct order on the right for the recommended power-up sequence.
Answer:
Explanation:
* SAN switches
* Tape libraries
* Disk storage
* Host servers
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NEW QUESTION: 1
Place the components on the left in the correct order on the right for the recommended power-up sequence.
Answer:
Explanation:
* SAN switches
* Tape libraries
* Disk storage
* Host servers
NEW QUESTION: 2
An integration updates a custom data object that uniquely maps to contacts within Eloqua using an email address. When net-new contacts are created via the integration, the contact is created with the accurate field values. However, subsequent updates to mapped fields of the custom object records are NOT reflected on the contact.
What is the cause of this?
A. The "Save to Contact Table" processing step within record services is NOT enabled.
B. You cannot update field values on the contact table from a custom object record.
C. The field mapping within the custom object is configured incorrectly.
D. The "Update Existing Record or Data Object" processing step within services is NOT enabled.
Answer: C
NEW QUESTION: 3
パーティショニングプラグインのステータスを表示するステートメントはどれですか。
A. SHOW STATUS PLUGINS WHERE Name = 'PARTITIONING';
B. SYSスキーマを使用します。プラグインのステータスを表示します。
C. SELECT PLUGIN_NAME、PLUGIN_VERSION、PLUGIN_STATUS FROM INFOMRATION_SCHEMA.PLUGINS WHERE PLUGIN_NAME = 'partition';
D. SHOW PLUGINS WHERE Name = 'partition';
Answer: C
NEW QUESTION: 4
You have a Microsoft SQL Server database that contains tables named Customers and Orders.
The tables are related by a column named CustomerID.
You need to create a query that meets the following requirements:
Returns the CustomerName for all customers and the OrderDate for any orders that they have placed.
Results must include customers who have not placed any orders.
Which Transact-SQL query should you use?
A. SELECT CustomerName, OrderDate
FROM Customers
LEFT OUTER JOIN Orders
ON Customers.CustomerID = Orders.CustomerID
B. SELECT CustomerName, OrderDate
FROM Customers
CROSS JOIN Orders
ON Customers.CustomerID = Orders.CustomerID
C. SELECT CustomerName, OrderDate
FROM Customers
RIGHT OUTER JOIN Orders
ON Customers.CustomerID = Orders.CustomerID
D. SELECT CustomerName, OrderDate
FROM Customers
JOIN Orders
ON Customers.CustomerID = Orders.CustomerID
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Reference:http://msdn.microsoft.com/en-us/library/ms177634.aspx